fix: removing duplicated tests and correcting some small solutions

unconventional-pairs/arthur-dolival-unconventional-pairs-tutorial.tex

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+\documentclass[10pt]{article}
+\usepackage[utf8]{inputenc}
+\usepackage{amsmath,amsthm,amssymb}
+\usepackage{fullpage}
+\usepackage{url}
+\pagenumbering{gobble}
+\usepackage{hyperref}
+\usepackage{graphicx}
+\input{statement/preamble.tex}
+
+\title{ Tutorial: Unconventional pairs}
+\author{Codeforces 1054 (Div. 3)}
+\date{}
+\begin{document}
+\maketitle
+\subsection*{Resumo da Estratégia}
+O problema pede para agrupar $n$ elementos em duplas de modo que a maior diferença absoluta entre os membros de qualquer par seja a menor possível. A solução utiliza uma abordagem \textbf{gulosa (greedy)} baseada em ordenação.
+
+\subsection*{Passos para a Solução}
+\begin{enumerate}
+    \item \textbf{Ordenação:} Ordene o array $a$ em ordem crescente: $a_1 \le a_2 \le \dots \le a_n$.
+    \item \textbf{Emparelhamento Adjacente:} Para minimizar a diferença entre dois números, eles devem estar o mais próximos possível na reta numérica. Portanto, a melhor estratégia é sempre emparelhar elementos vizinhos na sequência ordenada: $(a_1, a_2), (a_3, a_4), \dots, (a_{n-1}, a_n)$.
+    \item \textbf{Cálculo do Máximo:} Calcule a diferença $d_i = a_{2i} - a_{2i-1}$ para cada par $i$. A resposta final é o valor máximo entre todas essas diferenças.
+\end{enumerate}
+
+\subsection*{Complexidade}
+\begin{itemize}
+    \item \textbf{Tempo:} $O(N \log N)$ devido à ordenação. O cálculo das diferenças é $O(N)$.
+    \item \textbf{Espaço:} $O(N)$ para armazenar os elementos do array.
+\end{itemize}\end{document}

unconventional-pairs/arthur-dolival-unconventional-pairs.tex

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+\documentclass{maratona}
+
+\begin{document}
+\begin{ProblemaAutor}{}{Unconventional pairs}{1}{256}{Codeforces 1054 (Div. 3)}
+
+Um novo reality show de competição foi lançado na cidade. De acordo com as regras do programa, os participantes devem ser organizados de uma forma específica: dado um número par de pessoas, todos os participantes devem obrigatoriamente ser agrupados em duplas.
+
+Você recebeu um array de \( n \) inteiros \( a_1, a_2, \ldots, a_n \). Sabe-se que \( n \) é um número par. O objetivo é dividir os participantes em exatamente \( n/2 \) pares \( (a_{p_1}, a_{q_1}), (a_{p_2}, a_{q_2}), \ldots, (a_{p_{n/2}}, a_{q_{n/2}}) \). Cada índice do array original pode pertencer a apenas um único par.
+
+Para qualquer par \( (x, y) \), a \textbf{diferença} é definida pelo valor absoluto \( |x - y| \). A tarefa é formar as duplas de modo que a \textbf{maior diferença} encontrada entre todos os pares seja a \textbf{mínima possível}.
+
+Determine o menor valor possível para essa diferença máxima.
+
+\Entrada
+
+A entrada consiste em vários casos de teste. A primeira linha contém um único inteiro \( t \) (\( 1 \le t \le 10^4 \)), indicando o número de casos de teste.
+
+Para cada caso de teste:
+\begin{itemize}
+    \item A primeira linha contém um número par \( n \) (\( 2 \le n \le 2 \cdot 10^5 \)), representando o comprimento do array \( a \).
+    \item A segunda linha contém \( n \) inteiros \( a_i \) (\( -10^9 \le a_i \le 10^9 \)), representando os valores atribuídos a cada participante.
+\end{itemize}
+
+É garantido que a soma de \( n \) em todos os casos de teste não excede \( 2 \cdot 10^5 \).
+
+\Saida
+
+Para cada caso de teste, imprima um único número inteiro representando o \textbf{valor mínimo possível da diferença máxima} entre os elementos de todos os pares formados.
+
+\ExemploEntrada
+
+\begin{Exemplo}
+\texttt{2} & \texttt{1}\\
+\texttt{2} & \texttt{0}\\
+\texttt{1~2} & \\
+\texttt{4} & \\
+\texttt{5~5~5~5} & \\
+\end{Exemplo}
+
+
+
+\Notas
+
+No primeiro caso de teste, temos \( n=2 \) e os participantes possuem valores \(\{1, 2\}\). Como só existe uma forma de formar um par, a única diferença possível é \( |1 - 2| = 1 \). Portanto, a maior diferença mínima possível é 1.
+
+No segundo caso de teste, temos \( n=4 \) com os valores \(\{5, 5, 5, 5\}\). Como todos os participantes possuem o mesmo valor, qualquer par formado terá uma diferença de \( |5 - 5| = 0 \). Assim, a diferença máxima entre todos os pares é 0, que é o valor ótimo.\end{ProblemaAutor}
+\end{document}

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unconventional-pairs/problem.json

@@ -44,7 +44,7 @@
     "solutions": {
         "main-ac": "ac.cpp",
         "alternative-ac": [],
-        "wrong-answer": [],
+        "wrong-answer": ["wa.cpp"],
         "time-limit": [],
         "time-limit-or-ac": [],
         "time-limit-or-memory-limit": [],

unconventional-pairs/src/ac.cpp

@@ -2,22 +2,24 @@
 
 using namespace std;
 
+int main() {
+    int t;
+    cin >> t;
+    while (t--) {
+        int n;
+        cin >> n;
+        vector<int> nums(n);
+        for (int i = 0; i < n; i++)
+            cin >> nums[i];
 
-int main(){
-   int t; cin >> t;
-   while (t--) {
-      int n; cin >> n;
-      vector<int> nums(n);
-      for (int i = 0; i < n; i++) cin >> nums[i];
-   
-      sort(nums.begin(), nums.end());
-   
-      int minDiff = INT_MAX;
-      for (int i = 1; i < n; i++) {
-         minDiff = min(minDiff, nums[i] - nums[i - 1]);
-      }
-   
-      cout << minDiff << endl;
-   }
-   return 0;
+        sort(nums.begin(), nums.end());
+
+        int minDiff = numeric_limits<int>::min();
+        for (int i = 1; i < n; i+=2) {
+            minDiff = max(minDiff, nums[i] - nums[i - 1]);
+        }
+
+        cout << minDiff << endl;
+    }
+    return 0;
 }

unconventional-pairs/src/wa.cpp

@@ -0,0 +1,23 @@
+#include <bits/stdc++.h>
+
+using namespace std;
+
+
+int main(){
+   int t; cin >> t;
+   while (t--) {
+      int n; cin >> n;
+      vector<int> nums(n);
+      for (int i = 0; i < n; i++) cin >> nums[i];
+   
+      sort(nums.begin(), nums.end());
+   
+      int minDiff = INT_MAX;
+      for (int i = 1; i < n; i++) {
+         minDiff = min(minDiff, nums[i] - nums[i - 1]);
+      }
+   
+      cout << minDiff << endl;
+   }
+   return 0;
+}

unconventional-pairs/unconventional-pairs-tutorial.tex

@@ -5,6 +5,8 @@
 \usepackage{url}
 \pagenumbering{gobble}
 \usepackage{hyperref}
+\usepackage{graphicx}
+\input{statement/preamble.tex}
 
 \title{ Tutorial: Unconventional pairs}
 \author{Codeforces 1054 (Div. 3)}

unconventional-pairs/unconventional-pairs.tex

@@ -28,6 +28,7 @@ Para cada caso de teste:
 Para cada caso de teste, imprima um único número inteiro representando o \textbf{valor mínimo possível da diferença máxima} entre os elementos de todos os pares formados.
 
 \ExemploEntrada
+
 \begin{Exemplo}
 \texttt{2} & \texttt{1}\\
 \texttt{2} & \texttt{0}\\